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Date: 2007-01-10 09:15 am (UTC)no subject
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Date: 2007-01-10 03:47 pm (UTC)Для комплекта , так сказать ...............
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Date: 2007-01-11 04:38 am (UTC)Это делается путем асимптотического вычисления log n! двумя способами: арифметическим, через кратности простых делитетелей, и аналитическюм, через Стирлинга, причем достаточно очень грубого Стирлинга, log n!=nlog n+O(n).
Из вышенаписанной формулы интересующая тебя легко выводится с помощью абелева суммирования.